&testar is of **int type. Try this:

int testar[] = {1,2,3};
int * ptestar;
ptestar = testar+1;

P.S.

You can expect quick answers with this type of questions (C language question unrelated to the IDE or STM32) in other general C programming forums.

ptestar = testar+1;

is not equivalent to

ptestar = &testar+1;

The former is the same as

ptestar = &testar[1];

This is not what I am seeking to do, which is to get a pointer to a location just beyond the bounds of the array to find the array size by the method I describe in this thread:
http://www.openstm32.org/tiki-view_forum_thread.php?forumId=7&comments_parentId=1612

I have given up on that method. I realize now there is no advantage to doing it that way over the use of the sizeof operator.

Hi,

If you want to have the address after the testar array you must declare ptestar as a pointer to a pointer to int (as it is really the address of an array of 3 ints...):

int **ptestar = &testar+1;

However, there is two things to note about your code:

1. If you follow strictly the C standard, your C program is not standard compliant, as pointer arithmetic is restricted to stay inside a single C object, while you code use pointer arithmetic to point to a integer array located after the testar object
2. If you want to be clearer that what follows testar is not another integer array, you may devlare ptestar as a pointer to void:

   void *ptestar = &testar+1;

3. Obviously, the testar declaration must be an array definition that provides the compiler with the size of the array; it cannot be an external declaration of a variable size array as, in this case, the compiler will not have any way, at compile time, to know the size of the array: it will only be known at link time, too late for the compiler to use it.

Hope this helps,

Bernard (Ac6)